0=-1x^2+1.14x+3.5

Solution for 0=-1x^2+1.14x+3.5 equation:

0=-1x^2+1.14x+3.5

We move all terms to the left:

0-(-1x^2+1.14x+3.5)=0

We add all the numbers together, and all the variables

-(-1x^2+1.14x+3.5)=0

We get rid of parentheses

1x^2-1.14x-3.5=0

We add all the numbers together, and all the variables

x^2-1.14x-3.5=0

a = 1; b = -1.14; c = -3.5;
Δ = b2-4ac
Δ = -1.142-4·1·(-3.5)
Δ = 15.2996
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.14)-\sqrt{15.2996}}{2*1}=\frac{1.14-\sqrt{15.2996}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.14)+\sqrt{15.2996}}{2*1}=\frac{1.14+\sqrt{15.2996}}{2}
$